![]() ![]() ![]() In case you want to replace multiple occurrences of the searchedObj you can use a classic for loop: for(let i = 0 i < myArray. Please note that both of the above examples assume that you have only one instance of the searchedObj in myArray. If callbackFn never returns a truthy value, findIndex () returns -1. findIndex () then returns the index of that element and stops iterating through the array. Find and replace multiple occurrences of the same object in an array The find () method in JavaScript searches through an array and returns the first element that satisfies a specified condition. It calls a provided callbackFn function once for each element in an array in ascending-index order, until callbackFn returns a truthy value. If we have a homogeneous object structure of the array we can just compare the elements in the array based on a specific field: const myArray = [Ĭonst searchedObj = Ĭonst i = myArray.findIndex(x => deepEqual(x, searchedObj)) Find and replace an object in an array with the same structure when the objects in the array have different structuresįor both of these cases, we will use the findIndex() method. We can use the find () method to find an object in an array of objects in JavaScript by its property value. Using JavaScript filter () to Find an Object in Array The filter () method works like the find () method in JavaScript. ![]() when all the objects in the array share the same structure There are various methods to check an array includes an object or not.If the element is not found, it returns -1. There are 2 cases for searching and replacing an object in a Javascript array: objectRegistry.find (object) Type: type UnknownObject Record type find (query: UnknownObject unknown) > ( string object: UnknownObject, filePath: string ) If theres an identity match ( ), it returns the source file path where the object was instantiated. Using findIndex () : findIndex () method is used to find the index of the first element in the array based on a function parameter.
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